Interesting Math Equation
Posted: April 6th, 2004, 9:01 pm
a few days ago I can accross the equation: e^(2pi*i)-1=0
therefore
e^(2pi*i)=1
ln(e^(2pi*i))=ln(1)
2pi*i=0
since 2 and pi are both constants, you divide bot out and are left with: i=0
but 0 is a real number
but i is an imaginary number
how can an imiganary number be the same as a real number?
therefore
e^(2pi*i)=1
ln(e^(2pi*i))=ln(1)
2pi*i=0
since 2 and pi are both constants, you divide bot out and are left with: i=0
but 0 is a real number
but i is an imaginary number
how can an imiganary number be the same as a real number?