STEP in C++

[ccb056]

I know that when using this code:

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x++;

that it increases x by 1, but what code would I use to increase x by 10, or by 0.1?

[Smartweb]

x *= 10, x *= 0.1.

For the second to work x has to be a double.

[ccb056]

i don't understand, where would I place that code

would I replace

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x++;

with

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x *= 10;

to increase by a factor of 10?

[Smartweb]

right

[ccb056]

so, if C was a constant, could I use:

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x *=0.1*C;

[ccb056]

i have used your code, and my output is always zero for this program

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#include <iostream>
int main ()
{
double C=299792458;
double X=0;
double Y=0;
double V=0;
/*
V=(V1+V2)/(1+((V1*V2)/(C^2)))
*/
while (X<C)
{
cout<<"V1="<<X<<"\n";
cout<<"V="<<(X+X)/(1+((X*X)/(C*C)))<<"\n";
X*=0.1*C;
}
return 0;
}

[Smartweb]

I'm not a C++ expert. Often C++ doesn't do quite as you like it to.

[ccb056]

ha, could you do what I'm trying to do in c++ in VB?

[Smartweb]

The result would be more predictable, but it woudl take a little bit longer.

[Tebow2000]

lol he probably could

[ccb056]

The result would be more predictable, but it woudl take a little bit longer.

that is why C++ > VB

[Smartweb]

VB's advantage is that the result is predictable. And GUI's are a lot easier.

[ccb056]

but c++ has faster/more efficent code and is better for a heavy math environment

[Smartweb]

I like C++'s portability more than anything. I can write a program in Windows that I can compile in Linux with no changes.

[ccb056]

and there are free compilers you can get for c++ legally

[ccb056]

here is the code for increasing x by y

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x += y;